<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:media="http://search.yahoo.com/mrss/"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:wfw="http://wellformedweb.org/CommentAPI/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
	xmlns:slash="http://purl.org/rss/1.0/modules/slash/"
	>

<channel>
	<title>全部和的加法数字组合 - 四号程序员</title>
	<atom:link href="https://www.coder4.com/archives/tag/%E5%85%A8%E9%83%A8%E5%92%8C%E7%9A%84%E5%8A%A0%E6%B3%95%E6%95%B0%E5%AD%97%E7%BB%84%E5%90%88/feed" rel="self" type="application/rss+xml" />
	<link>https://www.coder4.com</link>
	<description>Keep It Simple and Stupid</description>
	<lastBuildDate>Sat, 02 Jun 2012 11:51:22 +0000</lastBuildDate>
	<language>en-US</language>
	<sy:updatePeriod>
	hourly	</sy:updatePeriod>
	<sy:updateFrequency>
	1	</sy:updateFrequency>
	<generator>https://wordpress.org/?v=6.8.3</generator>
	<item>
		<title>全部和的加法数字组合</title>
		<link>https://www.coder4.com/archives/3320</link>
					<comments>https://www.coder4.com/archives/3320#respond</comments>
		
		<dc:creator><![CDATA[coder4]]></dc:creator>
		<pubDate>Sat, 02 Jun 2012 11:51:22 +0000</pubDate>
				<category><![CDATA[算法&数据结构]]></category>
		<category><![CDATA[全部和的加法数字组合]]></category>
		<guid isPermaLink="false">http://www.coder4.com/?p=3320</guid>

					<description><![CDATA[输入两个整数 n 和 m，从数列1，2，3.......n 中随意取几个数， 使其和等于 m ,要求将其中所有的可能组合列出来。 就是回溯么，这回路径改用stack数组模拟做了。 // n numbers, print all sum=m int stack[1024]; int pos = 0; void sum(int* arr, int n, int m, int i, int s) { if(i==n &#124;&#124; s==m) { i[......] 继续阅读]]></description>
		
					<wfw:commentRss>https://www.coder4.com/archives/3320/feed</wfw:commentRss>
			<slash:comments>0</slash:comments>
		
		
			</item>
	</channel>
</rss>
